The modified area is (1/48) (2πr(4h+3r))
<u>Step-by-step explanation:</u>
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
We need to solve x+2y=11 for x
Let's start by adding -2y to both sides
x+2y -2y = 11-2y
x= -2y+11
Now substitute -2y+11 for x in x-2y =-1
x-2y=-1
-2y+11-2y=-1
-4y+11=-1
Add -11 to both sides
-4y+11-11=-1-11
-4y=-12
Divide both sides by -4
-4y/-4 = -12/-4
y= 3
Substitute 3 for y in x=-2y+11
x= -2y+11
x = (-2)(3)+11
x=-6+11
x=5
The answer is x=5 and y=3
(5,3)
I hope that's help:)
No solution means u can graph the two equations and it would form parallel lines and would never intersect while, no real solution when graph the two equations would form the same line. When dealing with absolute value equation an equation with a degree larger than one,theres a chance it can be multiple solutions
Answer:
<h3>x = 1.54 or x = - 4.54 to 2 decimal places</h3>
Step-by-step explanation:
x² + 3x - 7 = 0
Using the quadratic formula
a = 1 b = 3 c = - 7
Hope this helps you
