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3 years ago

The point I (–4, –1) is rotated 90 about the origin. What is the image of I?

Mathematics

1 answer:

ohaa [14]3 years ago

6 0

9514 1404 393

Answer:

I'(1, -4)

Step-by-step explanation:

The transformation for rotation 90° about the origin is ...

(x, y) ⇒ (-y, x)

I(-4, -1) ⇒ I'(1, -4)

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James tosses a coin 40 times and gets 26 heads and 14 tails. what is the relative frequency of tails?

NeTakaya

Answer:

Answer is B

Step-by-step explanation:

TAILS = 14

TOTAL = 40

14/40 × 100= 35%

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3 years ago

Y is directly proportional to x squared. if y=12 when x=2 find x when y=48

Alexxx [7]

Answer:

x = 4

Step-by-step explanation:

y = kx²

NOTE: k is constant for proportionality

putting values for x and y

if x is 2

and y is 12

12 = k(2)²

12 = k4

12 = 4k

divide both sides by coefficient of k

12÷4 = 4k ÷ 4

k=3

substitute 3 for k

therefore when

y is 48

and k is constant 3

then x will be:

48=3x²

divide both sides by coefficient of x²

48 divide by 3 = 3x² divide by 3

16=x²

take the square root of both sides

√16 = √x²

x = 4

8 0

3 years ago

Firsft second third of forth one

IrinaVladis [17]

Answer:

any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions. ... So, any terminating decimal is a rational number.

Step-by-step explanation:

7 0

3 years ago

HOW DO THE EXPRESSION 4(3+X) AND (3+3+3+3)+(X+X+X+X) COMPARE TO ANOTHER

UkoKoshka [18]

They are equal to one another because 4(3+x) can be rewritten using the distributive property as 4(3)+4x or 3+3+3+3+x+x+x+x

8 0

3 years ago

Find domain of y=rad20-6x

Evgesh-ka [11]

Domain, on an "even root" context, means, an even root cannot have a negative radicand, since say for example $\bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25$

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

$\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x$

now, if "x" is 10/3, let's see $\bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0$

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example $\bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}$

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish

5 0

3 years ago