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3 years ago

Find the 75th term of the following arithmetic sequence. 6, 11, 16, 21,

Mathematics

1 answer:

katrin [286]3 years ago

8 0

Answer:

The 75th term in the sequence is 16

Step-by-step explanation:

The 75th term of a sequence can be considered as the term that is in the position at 75% along the sequence. This is assuming that the sequence has been sorted already from lowest value to highest value

In this sequence, which has 4 terms, we can find the 75th term by finding what term is at 75% (or three-quarters) along the sequence.

To find the 75th term:

Multiply the number of terms by 0.75 (or 75%/100%) :

0.75*4 terms= 3

Then, we find the value of the term that is at position 3 from the left (lowest number)

In this case, the term that is at the 3rd position from the left is 16

Thus, the 75th term in the sequence is 16

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3 years ago

Which statement compares the two numbers correctly?

Over [174]

Answer:

D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth

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Step-by-step explanation:

A) six times one tenth plus three times one hundredth plus two times one thousandth < six hundred twenty-nine thousandths

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<629000 FALSE

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C) six hundred twenty-nine thousandths < six times one tenth plus three times one hundredth plus two times one thousandth

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D) six hundred twenty-nine thousandths > six times one tenth plus three times one hundredth plus two times one thousandth

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Hope This Helps!!!

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3 years ago

Got half not sure of the rest through

bezimeni [28]

Answer:

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Step-by-step explanation:

make the denominators congruent

8/12 and 9/12

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2 years ago

Changle. Show all work. Round each length to the nearest tenth and each angle to the

Sedaia [141]

Answer:

Part 1) $BC=12.2\ units$

Part 2) $m\angle A=55^o$

Part 3) $m\angle C=35^o$

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=7^2+10^2$

$AC^2=149\\AC=12.2\ units$

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

$tan(A)=\frac{BC}{AB}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{10}{7}$

using a calculator

$m\angle A=tan^{-1}(\frac{10}{7})=55^o$

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

$m\angle A+m\angle C=90^o$ ----> by complementary angles

substitute the given value

$55^o+m\angle C=90^o$

$m\angle C=90^o-55^o=35^o$

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3 years ago