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2 years ago

Find the 75th term of the following arithmetic sequence. 6, 11, 16, 21,

Mathematics

1 answer:

katrin [286]2 years ago

8 0

Answer:

The 75th term in the sequence is 16

Step-by-step explanation:

The 75th term of a sequence can be considered as the term that is in the position at 75% along the sequence. This is assuming that the sequence has been sorted already from lowest value to highest value

In this sequence, which has 4 terms, we can find the 75th term by finding what term is at 75% (or three-quarters) along the sequence.

To find the 75th term:

Multiply the number of terms by 0.75 (or 75%/100%) :

0.75*4 terms= 3

Then, we find the value of the term that is at position 3 from the left (lowest number)

In this case, the term that is at the 3rd position from the left is 16

Thus, the 75th term in the sequence is 16

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3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

Read 2 more answers

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oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

because, since it's negative the closer the negative number is closer to 0 its number is lower (-) like -4 is farther away from the 0 than -3.

5 0

2 years ago