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Paraphin [41]
3 years ago
5

I need help. ASAP! Divide. (3b^3 – 10b^2 + 4) ÷ (3b – 1)

Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Step-by-step explanation:

try surfing how to divide a function by the long division method

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In order to make the expression below equivalent to ğ x + 6, which additional operation should be included in the
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B

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Can you answer those 2 questions please?!thank you
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Answer:

Question 1: Fraction

Question 2: Equal

Step-by-step explanation:

I know Q1 is right, I'm not so sure about Q2 so I'm sorry if that's wrong

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Last month, Brooklyn worked 255 hours for $750 per hour at her job at the store. How much did she earn the last month
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10 points
Blababa [14]

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i think its A

Step-by-step explanation:

5 0
3 years ago
7. Are the ordered pairs below an arithmetic sequence or geometric
DochEvi [55]

Answer:

8. Arithmetic Progression

9. f(9) = 300

Step-by-step explanation:

Given

\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3

This gives:

d = 45 - 55 = 35 - 45 = 25 - 35

d = -10 = -10 = -10

d=-10

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

f(n) = f(1) + f(n-1)

To find f(9), we substitute 9 for n

f(9) = f(1) + f(9-1)

f(9) = f(1) + f(8)

We need to solve for f(8); substitute 8 for n

f(8) = f(1) + f(8 - 1)

f(8) = f(1) + f(7)

We need to solve for f(7); substitute 7 for n

f(7) = f(1) + f(7 - 1)

f(7) = f(1) + f(6)

We need to solve for f(6); substitute 6 for n

f(6) = f(1) + f(6 - 1)

f(6) = f(1) + f(5)

We need to solve for f(5); substitute 6 for n

f(5) = f(1) + f(5 - 1)

f(5) = f(1) + f(4)

From the function, f(4) = 25 and f(1) = 55.

So:

f(5)=55 + 25

f(5)=80

f(6) = f(1) + f(5)

f(6) = 55 + 80

f(6) = 135

f(7) = f(1) + f(6)

f(7) = 55 + 135

f(7) = 190

f(8) = f(1) + f(7)

f(8) = 55 + 190

f(8) = 245

f(9) = f(1) + f(8)

f(9) = 55 + 245

f(9) = 300

8 0
3 years ago
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