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2 years ago

Please help please help please help you

Mathematics

2 answers:

tatyana61 [14]2 years ago

4 0

40 students prefer vanilla. To get this answer you need to multiply 200 times 0.2 because you are trying to find 20%

Tomtit [17]2 years ago

4 0

I think it’s b. 20 but ur choice

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Sports Feet is having a sale on the Rebound basketball shoe. The shoe comes in four different colors (black, red, white, or gold

koban [17]

8 different styles
4x2=8
If you want to answer future questions like this then you multiply the numbers of the items.

8 0

3 years ago

2z z =-5 divided by -2

polet [3.4K]

Answer:

-3x-y=5

y-2z=7

x-4y+z=-9

Step-by-step explanation:

3 0

2 years ago

If p and q are non-zero rational numbers, and s and t are irrational numbers, select all of the statements that are always false

Svetllana [295]

Answer:

The false choices are A, C, and E

Step-by-step explanation:

Let's make an example:

p=1

q=2

s=sqrt(3)

t=sqrt(6)

Since pq=1*2=2, the answer is rational and A is false.

Since pt=1*sqrt(6)=sqrt(6), the answer is irrational and B is true.

Since p/q=1/2=0.5, the answer is rational and C is false.

Since st=sqrt(3)*sqrt(6)=sqrt(18), the answer is irrational and D is true.

Since s/t=sqrt(3)/sqrt(6)=sqrt(1/2), the answer is irrational and E is false.

4 0

3 years ago

Line f has a slope of -3. what is the slope of the line that is parallel to line f

andre [41]

Answer:

A line parallel has the same slope, so -3

8 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago