it's quite simple. all you need too do is add the total amount then divide
group A (box one) =(0.85). Group A (directly under the first one) =(0.15). Group B do 34 + 14 to get 48 then you divide 34÷48 to get (0.71) that is your answer to the first box in Group B then you do the exact same thing as you did in the first one, but swich 14 for 34 and you will get (0.29)
Simplified to make it easier to read.
Group 1. (0.85 0.71)
Group 2. (0.15 0.29)
Can you mark me Branliest. plz
Answer:
The equation represents this situation and its solution are m + 68 = 185; m = 117 ⇒ A
Step-by-step explanation:
Let us solve the question
∵ Joanna is driving 185 miles to visit her family
∴ The total distance she is driving = 185 miles
∵ She drives 68 miles in the morning
∴ d = 68 miles
∵ She stops for lunch and then drives the rest of the distance
∵ m represents the number of miles she drove after lunch
∴ d = m miles
∵ d + d = the total distance she is driving
∴ m + 68 = the total distance she is driving
∵ The total distance she is driving = 185 miles
∴ m + 68 = 185
∴ The equation represents this situation is m + 68 = 185
→ To solve the equation subtract 68 from both sides
∵ 68 - 68 + m = 185 - 68
∴ m = 117 miles
∴ The solution is m = 117
Answer:
d
Step-by-step explanation:
There are only three shapes that can form tessellations: the equilateral triangle, square, and regular hexagon. Any one of these three shapes can be duplicated infinitely to fill a plane with no gaps. Many other types of tessellation are possible under different constraints.
Answer:
-4 - 12x / -4×(1+3x)
Step-by-step explanation:
-2+(-6)×2x-2
- multiplying an odd number of negative terms makes the product negative
(+(-6)= - ) -2-6×2x-2
- calculate the product
(6×2=12) - -2-12x-2
-calculate the difference
(-2-2=-4) - -4-12x
SOLUTION: -4-12x
/
-2+(-6)×2x-2
- calculate the difference
(-2-2) - -4+(-6)×2x
- factor out - 2×2 from the expression = -2×2(1+3x)
-multiply the numbers
(2×2=4) - -4×(1+3x)
SOLUTION: -4×(1+3x)
*both solutions are correct but i wasnt sure, which method you would rather use*