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▹ Answer
<em>16q + 4</em>
▹ Step-by-Step Explanation
10q + 5 + 6q - 1
10q + 6q + 5 - 1
16q + 4
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Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
80 parrots were purchased.
Step-by-step explanation:
Let the total number of parrots be k.
If 20% (or 20/100 = 1/5) flew away and 5% (5/100 = 1/20) died, the remaining parrots will be k – (¹/₅k + ¹/₂₀k) = k – ¼k = ¾k.
Of the remaining, 45% (or 45/100 = 9/20) were sold, which means the total number of sold parrots will be ¾k × ⁹/₂₀ = ²⁷/₈₀k.
The remaining parrots = ¾k – ²⁷/₈₀k = ³³/₈₀k = 33
k = 33 × ⁸⁰/₃₃ = 80 parrots were purchased.
Answer:
its up.
Step-by-step explanation:
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