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stiv31 [10]
3 years ago
6

Can someone solve for the question mark? 6x + ? = 10

Mathematics
2 answers:
sukhopar [10]3 years ago
3 0
Theirs no such thing lol
Vladimir [108]3 years ago
3 0
Depends, the lowest being X=1 and it being 6 alone
6(1) + ? = 10
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Simplify the expression. <br> -3(b – 7)
pychu [463]
-3(b - 7)

Distributive property

-3*b = -3b

-3*7 = -21

-3b + 21

Answer:  -3b + 21

6 0
3 years ago
Determine the maximum number of zeros of the polynomial function -8x^4-x^2+2 a. 1 c. 3 b. 4 d. 2 Please select the best answer f
alexgriva [62]
Generally speaking, the number of solutions to an algebraic equation is equal to the exponent of the highest power.  so the answer is b.4


6 0
3 years ago
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3 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
3 0
3 years ago
Suppose we are given the following.
Mashutka [201]

Answer:

Slope of line 1 = 3

Slope of line 2 = -3

Slope of line 3 = -1/3

Line 1 and 2 = perpendicular

Line 1 and 3 = perpendicular

Line 2 and 3 = perpendicular

Step-by-step explanation:

trust me its correct

pls mark me as brainliest

6 0
3 years ago
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