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a_sh-v [17]
3 years ago
13

What is an extraneous solution to the equation b/b-3 -5/b=3/b-3 ?

Mathematics
2 answers:
castortr0y [4]3 years ago
8 0

Answer:B= 3

Step-by-step explanation:

storchak [24]3 years ago
5 0
\frac{b}{b-3} - \frac{5}{b} = \frac{3}{b-3}  \\   \frac{ b^{2} -5(b-3)}{b(b-3)} =\frac{b}{b-3} \\  \frac{ b^{2} -5b+15}{b^2-3b} =\frac{b}{b-3} \\ (b-3)(b^{2} -5b+15)=b(b^2-3b) \\ b^3-8b^2+30b-45=b^3-3b^2 \\ 5b^2-30b+45=0 \\ b^2-6b+9=0 \\ (b -3)(b-3)=0 \\ b=3

To check: 3/3-3 - 5/3 = 3/0 - 5/3 which is not defined.

Therefore, b = 3 is an extraneous solution.
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a number, half of that number, and one-third of that number are added. The result is 22. What is the original number
aliina [53]
<span>A number, half of that number, and one-third of that number are added.
This statement can be expressed as:
x + (1/2)x + (1/3)x

The total is 22
</span>x + (1/2)x + (1/3)x = 22

So let's look for x
x + (1/2)x + <span>(1/3)x = 22
</span>(6x + 3x + 2x) / 6 = 22
11x = 132
x = 12

So the original number is 12.
7 0
3 years ago
12) Write the equation of the quadratic whose vertex is (-2,3) and a = -3.
mrs_skeptik [129]
4/1&373; I need points ;)
4 0
3 years ago
The graph of the step function g(x) = –⌊x⌋ + 3 is shown.
Blababa [14]

Using it's concept, the domain of the function is given as follows:

{x| –2 ≤ x <= 5}

<h3>What is the domain of a function?</h3>

The domain of a function is the set that contains all possible input values for the function, that is, the values for which the function is defined.

The function described in this problem is defined from x = -2 until x = 5 hence the domain of the function is given as follows, by the interval:

{x| –2 ≤ x <= 5}

More can be learned about the domain of a function at brainly.com/question/10891721

#SPJ1

3 0
1 year ago
I Will give out brainliest help ASAP
kirza4 [7]

Step-by-step explanation:

f(x) = 2x² + 9

f(5) = 2(5)² + 9

= 2(25) + 9

= 50 + 9

= 59

6 0
3 years ago
Please help me get the right answer?!
Aleksandr-060686 [28]
The answer is A, \frac{1}{81}. This is because when plugging in -2 for x, the expression will look like this: 9^{-2}. To make the exponent positive, you have to flip it into a fraction. Then it will be \frac{1}{9^2}. Lastly, you simplify the denominator into 81.
4 0
3 years ago
Read 2 more answers
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