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2 years ago

5

a chocolate company selects 800 random packages to check their weight. It finds that 12 packages have an incorrect weight. How m

any packages out of 4000 should the company predict to have the incorrect weight.

1 answer:

Lerok [7]2 years ago

5 0

Answer:

1.5% of 4000 or 60

Step-by-step explanation:

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Laura bought 23 pounds of sugar for $12.<br> How many dollars did she pay per pound of sugar?

Vikki [24]

Answer:

≈ $0.52 per pound

Step-by-step explanation:

12/23 ≈ $0.52

6 0

2 years ago

a boutique handmade umbrella factory currently sells 22500 umbrellas per year at a cost of 9 dollars each. in the previous year

sergij07 [2.7K]

Answer:

The maximum revenue of the two years is $ 394,500 .

Step-by-step explanation:

Given as :

The current number of selling of umbrellas = 22500

The price of each umbrellas = $ 9

So, The Total price of 22500 umbrellas at $ 9 per umbrellas = $ 9 × 22500

I.e The Total price of 22500 umbrellas at $ 9 per umbrellas = $ 202,500

Again ,

The total number of umbrellas sold previous year = 12000

The price of umbrellas = $ 16

So, The Total price of 12000 umbrellas at $ 16 per umbrellas = $ 16 × 12000

I.e The Total price of 12000 umbrellas at $ 16 per umbrellas = $ 192,000

So, The maximum revenue of the two years = $ 202,500 + $ 192,000

I.e The maximum revenue of the two years = $ 394,500

Hence The maximum revenue of the two years is $ 394,500 . Answer

3 0

3 years ago

What is the ratio 15 to 35 written as a fraction in lowest terms?

dmitriy555 [2]

B 3/7 because 15 divided by 5 = 3 and 35 divided by 5 = 7

4 0

3 years ago

Read 2 more answers

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

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3 years ago

Find the area.<br> 7 m<br> 4 m<br> 4 m<br> square meters

morpeh [17]

Answer:

gianas

Step-by-step explanation:

antetekumpo the nba rocket fuel

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3 years ago