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2 years ago

What is the equation of the line with a slope of 2 through (–4, 6) in point-slope form?

Mathematics

1 answer:

Sloan [31]2 years ago

7 0

In point-slope form, the equation is :

Y-6=2(x+4)

Hope this helps✨❤️

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Please solve for me it's urgent. A rectangle has 10 and 6cm each. find the area of a square with the same perimeter as that of t

elena55 [62]

Answer:

64 cm²

Step-by-step explanation:

Firstly,let us lay down the clues;

So, we have been given the Length and Width of the rectangle.

Rectangle;

Length= 10 cm

Width=6 cm

We know that

Perimeter= 2L + 2W

Perimeter= 10+10+6+6

Perimeter =32 cm

In the questionnaire, it is mentioned that a square has the same perimeter as the rectangle. That means, the perimeter of the square is similar to the one of the rectangle which is 32 cm.

So,

Perimeter of square =32 cm

Length of one side of the square =32÷4

=8 cm

Area= L × W

Area= 8 cm× 8 cm

Area= 64 cm²

Hope it helps.

5 0

2 years ago

Maria has 2 more than 4

Ksju [112]

Answer:

2022

Step-by-step explanation:

2 + 4x = y

y = 2 + 4(505)

y = 2 + 2020

y = 2022

4 0

2 years ago

How many miles is 2/3

Hoochie [10]

1 mile = 1760 yards

=2/3*1760

2*586.66

=1173.33 yards

hope this helps

5 0

3 years ago

Is a function or not

Anna71 [15]

Answer:

that is indeed a function

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

6 0

3 years ago