Answer:
4
Step-by-step explanation:
So your equation is 1.6(x-y)/2
Since x=10, and y=5, we need to substitute the amounts in to the equation.
so...
1.6(10 -5)/2
Using PEMDAS, parenthesis comes first. So solve what 's in the parenthesis (10 - 5).
So..
1.6(5)/2
Next, multiply 1.6 by 5.
1.6 x 5 = 8.
So you are left with the equation
8/2
and 8 divided by 2 is...
4!
Answer:
8
Step-by-step explanation:
Given the expression
4t^6-r^10 we are to factorize in the form;
(2t^x+r^y)(2t^x-r^y)
First we need to factorize (2t^x+r^y)(2t^x-r^y)
![= (2t^x+r^y)(2t^x-r^y)\\= 4t^{2x}-2t^xr^y + 2t^xr^y - r^{2y}\\= 4t^{2x}-r^{2y}](https://tex.z-dn.net/?f=%3D%20%20%282t%5Ex%2Br%5Ey%29%282t%5Ex-r%5Ey%29%5C%5C%3D%204t%5E%7B2x%7D-2t%5Exr%5Ey%20%2B%202t%5Exr%5Ey%20-%20r%5E%7B2y%7D%5C%5C%3D%20%204t%5E%7B2x%7D-r%5E%7B2y%7D)
Compare ![4t^{2x}-r^{2y} \ with \ 4t^6-r^{10}](https://tex.z-dn.net/?f=4t%5E%7B2x%7D-r%5E%7B2y%7D%20%5C%20with%20%5C%204t%5E6-r%5E%7B10%7D)
![4t^{2x} = 4t^6\\t^{2x} = t^6\\equate \ the \ powers\\2x = 6\\x = 3\\](https://tex.z-dn.net/?f=4t%5E%7B2x%7D%20%3D%204t%5E6%5C%5Ct%5E%7B2x%7D%20%3D%20t%5E6%5C%5Cequate%20%5C%20the%20%5C%20powers%5C%5C2x%20%3D%206%5C%5Cx%20%3D%203%5C%5C)
Get y;
![r^{2y} = r^{10}\\2y = 10\\y = 5\\Hence \ x + y = 3+5 = 8](https://tex.z-dn.net/?f=r%5E%7B2y%7D%20%3D%20r%5E%7B10%7D%5C%5C2y%20%3D%2010%5C%5Cy%20%3D%205%5C%5CHence%20%5C%20x%20%2B%20y%20%3D%203%2B5%20%3D%208)
Hence the sum of x and y is 8
Answer:
D
Step-by-step explanation:
3x-4y=6
-4y=-3x+6
y=(3/4)x-(3/2)
positive slope with y-intercept at -3/2 corresponds to D
Answer:
B. Taking square root of both sides
Step-by-step explanation:
The first step given to us is
![(x+\frac{b}{2a} )^2=\frac{b^2-4ac}{4a^2}](https://tex.z-dn.net/?f=%28x%2B%5Cfrac%7Bb%7D%7B2a%7D%20%29%5E2%3D%5Cfrac%7Bb%5E2-4ac%7D%7B4a%5E2%7D)
When we take square root of both sides we obtain;
![x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2} }](https://tex.z-dn.net/?f=x%2B%5Cfrac%7Bb%7D%7B2a%7D%3D%5Cpm%20%5Csqrt%7B%5Cfrac%7Bb%5E2-4ac%7D%7B4a%5E2%7D%20%7D)
Therefore the corect answer is B
Answer:
need the whole question .....
Step-by-step explanation: