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svp [43]
3 years ago
5

Calculate the unit rate. A 5 gallon bucket of paint for $70.50​

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
Okay to find the unit rate you must find how much one bucket of paint costs so you divide 70.50/5 and then you will get 14.1 have a nice day (:
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What are the solutions of 3x2 + 14x + 16 = 0?
nevsk [136]

Good evening ,

Answer:

x = StartFraction negative 8 Over 3 EndFraction, –2

Step-by-step explanation:

3x² + 14x + 16 = 0

3x² + 6x + 8x + 16 = 0

(3x² + 6x) + (8x + 16) = 0

3x(x+2) + 8(x+2) = 0

(x+2)(3x+8) = 0

x = -2  ,  x = -8/3.

:)

5 0
3 years ago
Read 2 more answers
Michael is making a card for his dad's birthday. He's shaded a triangular section on the card where he wants to write his dad a
artcher [175]

Answer:

Option C (72)

Step-by-step explanation:

In the figure attached we can see a rectangle ABCD with length 12 cm and width 9 cm.

A  triangle PEF with height BE and base EF.

Since side AE = 3 cm, so side EB = EC = 9 - 3 = 6cm

and EF = AD = 12 cm

Now we will find the area of of the parts of the card that are not shaded.

Area of parts that are not shaded = Area of rectangle - area of shaded triangle

= (12×9) -

= 108 -

Option c) 72 cm² is the area of non shaded part.

Hope this helps!! -Mina

7 0
2 years ago
Read 2 more answers
How do I simplify this exponent problem???
Nikolay [14]

Hello from MrBillDoesMath!

Answer:

(3/4) a^(-5)b^(-3)c^2


Discussion:  

(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =

(18/24) a^ (-3-2) b^(2-5) c^(6-4) =

                  as  a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples

(3/4) a^(-5)b^(-3)c^2


Thank you,

MrB

8 0
3 years ago
WILL GIVE BRAINLIEST IF YOU HELP ME
Oduvanchick [21]
The answer is D. point S
8 0
3 years ago
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4. A statistician working for the National Basketball Association supplies the television announcers with interesting statistics
Sonbull [250]

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by  the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: p=\dfrac{300}{375}=0.8

Critical z-value for 90% confidence: z* = 1.645

Margin of error =z^*\sqrt{\dfrac{(1-p)p}{n}}

The margin of error in a 90% confidence interval estimate of p =1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038

Hence, the required margin of error = 0.038

7 0
3 years ago
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