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V125BC [204]
3 years ago
6

PLEASE HELP!!!!!!!!!!!!

Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

The answer to your question is: Option B is correct

Step-by-step explanation:

Which expression is equivalent to the square root of 80?

Find the prime factors of 80

80 = 2⁴5 then \sqrt{80}  = 4\sqrt{5} = \sqrt{2^{2}2^{2} 5 }

Option A which is 4 square root of 2 times the square root of 5  This option is incorrect

Option B which is square root of 2^4 times the square root of 5  This option is correct

Option C which is the square root of 2 times the square root of 2 times the square root of 5  This option is incorrect

Option D which is the square root of 2^2 times the square root of 2^2 times the square root of 5^2 This option is incorrect

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Check MyAnswer Please!!!
jok3333 [9.3K]
The equation x^2-9y^2=900 <span>defines a hyperbolic cylinder.
</span>
1. Divide the equation x^2-9y^2=900  by 900:
\dfrac{x^2}{900} - \dfrac{y^2}{100} =1.
This is the equation of conic section when z=0 (or z=const) and that is hyperbola equation.

2. To find the domain and the range you should express y:
\dfrac{y^2}{100} =\dfrac{x^2}{900} - 1 \\   \\ y^2= \dfrac{x^2}{9} -100 \\   \\ y=\pm  \sqrt{\dfrac{x^2}{9} -100}.
Since you have square root, 
\dfrac{x^2}{9} -100\ge 0 \\ x^2-900\ge 0 \\ (x-30)(x+30)\ge 0 \\ x\in(-\infty,-30)\cup (30,\infty). This is the domain, the range is y\in (-\infty,\infty).
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3 years ago
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