A rectangular field is 16m long and 10m wide . there is a path of uniform width all around it having an area of 120 m² .find the
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Answer:
- 1.375 seconds
- 35.25 feet
Step-by-step explanation:
A quadratic function y=ax^2 +bx +c is symmetric about the vertical line x=-b/(2a). That is the x-coordinate of the vertex (maximum or minimum).
Here, we have ...
h = -16t^2 +44t +5
t = -44/(2(-16)) = 11/8 = 1.375
It takes 1.375 seconds for the ball to reach its maximum height.
The height at that time is ...
h = (-16(11/8) +44)(11/8) +5 = (-22 +44)(11/8) +5 = 121/4 +5 = 141/4 = 35.25
The maximum height is 35.25 feet.
