Answer:
4= 29
+6
all I know is number fourr T-T I tried yw
Step-by-step explanation:
Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters
Part A: subtract 6 from both sides
Divide by -3 on both sides
X=-3
Part B: add like terms (-2K-3k)
Add 12 to both sides
Add 5k to both sides
Divide by 5 on both sides
K=3
Part C: distribute 6 into the parentheses
Add like terms together (36-5)
Subtract 1 from both sides
Subtract 36v from both sides
Divide by -30 on both sides
-1=v
I think you meant to have more of a problem stated.
Basically, you use the Law of Sines when you have 2 angles but the length of only one side.
The formula for this law is
a / sine(A) = b / sine(B) = c / sine(C)
HP = JP (since the opposite sides of an isosceles triangle are equal)
3x - 6 = x + 2
2x = 8
x = 4
Thus, HP = 3(4) - 6 = 12 - 6 = 6
JP = 4 + 2 = 6
JH = 2(4) = 8.