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Anika [276]
2 years ago
14

Vocabulary Which of the following describes the median of a data set?

Mathematics
2 answers:
Allushta [10]2 years ago
5 0

Answer:

C is the answer

Step-by-step explanation:

Natali [406]2 years ago
5 0

Answer:

C the sum of the data values divided by the total number of data value

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X - 2 + 3 =(-2) how do you solve this?
Ket [755]

Answer:

x = -3

Step-by-step explanation:

x-2+3=-2\\x+1=-2\\x=-3

7 0
2 years ago
Read 2 more answers
The painting shown at the right has an area of 220. What is the value of x?
tangare [24]

Answer:

9.76

Step-by-step explanation:

area of a rectangle = length * breadth

length = (2x + 3)

breadth = x

given area is 220 sq. inches.

thus,

220 = x * (2x+3)

220 = 2x² +3x

2x² + 3x -220 = 0

x = (-b + √ ( b²-4ac) ) ÷ 2a

x = ( -3 + √ ( 3² - 4*2*220) ) ÷ 2*2

x =9.76

5 0
2 years ago
What is the answer to (4.575 ÷ 275) × 2
const2013 [10]

Answer:

0.0334

Step-by-step explanation:

(4.575 ÷ 275) × 2

0.0167 * 2

Hope this helps!

6 0
2 years ago
Solve in simultaneou linear equation.
dangina [55]

Answer:

The bag costs 1500, while the umbrella cost 500

Step-by-step explanation:

Let the cost of the bag be b and the cost of the umbrella be u

Total cost is;

b + u = 2,000 •••••(i)

From the second part of the question;

b = 5u-1000 ••••••(ii)

Substitute ii into i

5u-1000 + u = 2000

6u = 2000 + 1000

6u = 3000

u = 3000/6

u = 500

To get b, substitute the value of u into equation ii

b = 5(500)-1000

b = 2500-1000

b = 1500

5 0
2 years ago
Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation
evablogger [386]
Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)


sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4}  \\ \\   \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4}  )=1 \\  sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  =1 \\  cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  =1 \\
2cos(x)sin\frac{ \pi }{4}  =1    \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2}  \\ 2cos(x) \frac{ \sqrt{2} }{2}  =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x)   =1 \\   \sqrt{2} cos(x)=1 \\
cos(x)= \frac{1}{ \sqrt{2} }  \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z
6 0
2 years ago
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