Answer:
1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²
2 / Find the area of an isosceles Δ DEF:
The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft
So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²
3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²
Step-by-step explanation:
write it neatly
Step-by-step explanation:
pls once more
Answer:

Step-by-step explanation:
When working with surds we need to take note of the roots present there.
To expand this equation we can do it the following way noting that √3 X √3 = 3
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<em>Expanding (1-√3)(⅓+√3)</em>
1 X 1/3 = 1/3
1 X √3 = √3
-√3 X 1/3 =-√3/3
√3 X √3 = 3
hence, expanding the equation, we have
1/3 + √3 -√3/3 + 3
We can simply group the like terms and add them up.
[1/3 +3] +[√3-√3/3]
10/3 + 
= 
Answer:

Step-by-step explanation:
<em>Hey there!</em>
Well using the given ratio,
3:4
And the area of the small shape we need to do,
72*72 = 5184
Now we can make the following fractions,
= 
Now we can solve,
3*x = 3x
4 * 5184 = 20736
3x = 20736
20736 / 3
x = 6912
So the area of the bigger shape is 6912 units^2
<em>Hope this helps :)</em>
X2 - 8x + 15 = 0
(x - 3)(x - 5) = 0
critical points are at 3 and 5