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3 years ago

Same thing as last. nearest 100th

Mathematics

2 answers:

bekas [8.4K]3 years ago

8 0

Answer:

452.39 mi^2

Step-by-step explanation:

A = πr^2

A = π (12mi)^2

A = 452.39 mi^2

Please mark Brainliest :D

Ede4ka [16]3 years ago

3 0

Answer:

finding area formula of a circle:

πr^2 (pie r (radius) squared)

Pie could equal: 22/7 or 3.14

Use 3.14 most likely,

Given information

Radius is: 12

(needs to be squared)

12 x 12 = 144

144 x 3.14 <------ (pie or π) = 452.16

452.16 rounded to the nearest hundredth is:

452.16 miles. (doesn't have a thousandths place so we can't really round but we should assume the number by itself)

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5x + y =7<br> 20x + 2 = y

kodGreya [7K]

Answer:

y = 6

x = 0.2

Step-by-step explanation:

5x + y =7

20x + 2 = y

5x(4) + y(4) = 7(4)

20x + 4y = 28

(20x = 28 - 4y) = (20x = y - 2)

28 - 4y = y - 2

30 - 4y = y

30 = 5y

y = 6

5x + y =7

20x + 2 = y

y = 7 - 5x

7 - 5x = 20x + 2

5 - 5x = 20x

5 = 25x

x = 0.2

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Use technology to find the p-value for the hypothesis test described below. the claim is that for a smartphone carrier's data

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Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

6 0

3 years ago