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2 years ago

If f(x)=5x^2-8, what is the value of F(-3)?

Mathematics

1 answer:

mr Goodwill [35]2 years ago

8 0

Answer:

F(-3)=5(-3)^2-8

=37

Step-by-step explanation:

Get it?

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Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

$y'(0)=16\implies-16=4C_1-4C_2$

$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

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3 years ago

Solve the problem: -10 + +10 =

mafiozo [28]

It equals zero negative plus positive equals zero

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2 years ago

Read 2 more answers

Use the diagram to find lengths. BP is the perpendicular bisector of AC. QC is the

faust18 [17]

Answer:

The length of the side PC is 34 cm.

Step-by-step explanation:

We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.

Suppose BP = 16 cm and AD = 90 cm.

As, it is given that AD = 90 cm and the three sides AB = BC = CD.

From the figure it is clear that AD = AB + BC + CD

So, AB = $\frac{90}{3}$ = 30 cm

BC = $\frac{90}{3}$ = 30 cm

CD = $\frac{90}{3}$ = 30 cm

Since the triangle, BPC is a right-angled triangle as $\angle$ PBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.