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bearhunter [10]
2 years ago
8

Someone help please!!!!

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
5 0

Answer:

x = -2

TU = 4

UB = 2

Step-by-step explanation:

you can add x^2 with 4x+10 and equate it to 6:

x^2 + 4x + 10 = 6

x^2 + 4x + 4

then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a

so it'll be   x = {-4±[√16 - 4(4)]}/2

x= -2

then u can substitute it and find TU and UB

TU= (-2)^2 = 4

UB= 4(-2)+10 = 2

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4. Rhombus QRST has diagonals intersecting at W. Point U is located on side QR and point V on diagonal RT
ad-work [718]

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Given:

In Rhombus QRST, diagonals QS and RT intersect at W and U∈QR and point V∈RT  such that UV⊥QR. (shown in below diagram)

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In triangles QWR and UVR,

m\angle QWR=m\angle VUR              (Right angles)

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By AA similarity postulate,

\triangle QWR\sim \triangle VUR

The corresponding sides in similar triangles are in same proportion,

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Hence, proved.

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