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Nikitich [7]
2 years ago
10

What are the solutions to x2 + 8x + 7 = 0?

Mathematics
1 answer:
Ymorist [56]2 years ago
6 0
The answer is x=-7 and x=-1
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What is the value of fraction 1 over 2x3 + 5.2y when x = 2 and y = 3?
mihalych1998 [28]
I think is 1/27.6 because 2x equals 4 and times 3 equals 12. 5.2y equals 15.6. Then 15.6 plus 12 equals 27.6.
4 0
3 years ago
Given the inequality below:<br><br> 3x-y&gt;4<br><br> Which is the graph of the solution set?
OLga [1]

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

6 0
3 years ago
A function f (x)=-8x^2. What is f (-3)?
Sveta_85 [38]
F(x)= -8x²

f(-3)= -8* (-3)²

f(-3)= -8 * 9

f(-3)= -72
8 0
3 years ago
Read 2 more answers
Please help, performance task: trigonometric identities
AnnZ [28]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

brainly.com/question/8120556

#SPJ1

4 0
1 year ago
Match the base to the corresponding height.
allochka39001 [22]

Answer:

I can't see the picture

Step-by-step explanation:

SORRY :(

7 0
2 years ago
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