Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Move it to half way to the other side the way a clock moves.
<span>A) 5x + 7y = 3
B) 2x + 3y = 1
Multiplying Equation B by -2.5
</span><span>B) -5x -7.5y = -2.5 Then adding this to Equation A)
A) 5x + 7y = 3</span>
-.5y = .5
y = -1
Since
<span>2x + 3y = 1 then
2x -3 = 1
then x = 2
</span>
You can turn it into a mixed number 1 83
--
100
565.487 units cubed
hope this helps:)
