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Akimi4 [234]
3 years ago
14

5 pounds 80 cents $1.40 per pound

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

What’s your question?

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HELP!!! 20 POINTS!!! URGENT!!!
VashaNatasha [74]

We know that :

\clubsuit  ln(A) - ln(B) = ln(\frac{A}{B})

\clubsuit  aln(x) = ln(x)^a

\clubsuit  ln(A) + ln(B) = ln(AB)

Using above ideas we can solve the Problem :

⇒ \frac{3}{8}ln(x + 3) = ln(x + 3)^\frac{3}{8}

⇒ ln(x - 3) - ln(x + 3)^\frac{3}{8} = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]

⇒ 4ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}] = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]^4 = ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}]

⇒ \frac{1}{3}lnx + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln(x)^\frac{1}{3} + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln[\frac{\sqrt[3]{x}(x - 3)^4}{\sqrt{(x + 3)^{3}}}]

Option 3 is the Answer

8 0
3 years ago
Find the sum of 3.0478 and 4.92 using the correct number of significant digits.
Nat2105 [25]

The sum of 3.0478 and 4.92 is 7.9678, which have 5 significant digits.

<u>Step-by-step explanation:</u>

We have , Number1 = 3.0478 and Number2  =4.92 . The significant digits of a number are digits that includes all digits except:

  • All leading zeros. For example, "013" has two significant figures: 1 and 3;
  • Trailing zeros when they are merely placeholders to indicate the scale of the number and  ,
  • Spurious digits introduced, for example, by calculations carried out to greater precision than that of the original data, or measurements reported to a greater precision than the equipment supports.

Here Number1 = 3.0478 and with significant digit rules Number2 = 4.9200 . Now, Sum of both numbers = Number1 + Number2

⇒Sum of both numbers = 3.0478 + 4.9200

⇒Sum of both numbers = 7.9678

∴ The sum of 3.0478 and 4.92 is 7.9678, which have 5 significant digits.

8 0
3 years ago
During his workouts last week, Allen jogged the same amount of time each day for 6 days. Use the following information to determ
Nataly [62]
He rode his bike 45 minutes each day:
45x6 = 270 total time cycled

Jogging time = total workout time - cycle time/6

360-270= 90/6= 15 minutes jogged each day

8 0
4 years ago
Answer the question pleaseeeee
Montano1993 [528]
Would you be able to upload a clear picture please
7 0
3 years ago
Pleasee help asap please help
KengaRu [80]

Answer:

q6 : b=-22

Q7.60×4=3h. 240=3h. 80=3h

4 0
2 years ago
Read 2 more answers
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