Question

If a rectangle has length x and width x+3, what is the perimeter of the rectangle in terms of x?

Answer 1

Answer:

$4x+6$ units

Step-by-step explanation:

Skills needed to solve: Order of Operations, Distributive Property, Perimeter Formula, Like Terms

1) To solve this problem, you need to understand the perimeter formula, and that is:

--> $P = 2(L+W)$

P = Perimeter

L = Length

W = Width

2) Based on that, we are given that:

$L = x$ (since the length is x)

$W = x+3$ (since the width is x+3)

3) After that, we substitute in the values:

$P = 2(L+W)$

$P = 2(x+(x+3))$

$x + (x+3) = x+x+3 = 2x+3$ (with like terms and addition)

so: $P=2(2x+3)$

Use distributive property, which is $a(b+c) = ab+ac$

get: $2(2x+3) = 2(2x) + 2(3)$

$2(2x) = 4x$

$2(3) = 6$

So: $P = 4x+6$

Hope this helps and have a nice day!! :) :]