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DENIUS [597]
3 years ago
14

At midnight, the temperature was 30 degrees Fahrenheit. By 6:00 am, IT had dropped 5 degrees Fahrenheit and by noon, it had incr

eased by 11 degrees Fahrenheit. WHAT was the temperature at noon? Please explain
Mathematics
1 answer:
Allisa [31]3 years ago
4 0
At noon, the temperature was 36 degrees. At midnight, the temperature was 30 degrees. By 6:00 am it drooped 5 degrees. Since it dropped 5 degrees, you subtract 5 from 30, which equals 25. It then increased by 11 degrees. Since the temperature increased, you add 11 to 25, which equals 36. At noon, the temperature was 36 degrees.
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16 OT 26
hram777 [196]

Answer:

Total = 166cm^2

Step-by-step explanation:

Given

See attachment

Required

Determine the surface area

The figure is made up of two cuboids and the surface area of a cuboid is:

Area = 2LB + 2LH + 2BH

Because the bottom part of the upper piece is not visible, the area is calculated as:

Area = 2LB + 2LH + BH

This gives:

Area = 2 * 5*4 + 2 * 4 * 2 + 5 * 2

Area = 66

For the bottom piece:

We calculate its area as Area = 2LB + 2LH + 2BH. However, the area of the invisible part will be subtracted.

So, we have:

Area = 2*3*5 + 2*3*5 + 2*5*5 - 2*5

Area = 100

The total surface area is:

Total = 66 + 100

Total = 166cm^2

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