Answer:
B. 22
Step-by-step explanation:
We know tan60=

Let common side be x
Tan = opp/adj= sqrt(3)

Transposing we get :

Now, we know that since the other triangle is a 45-45-90 triangle, we can state that the side adjacent to the given angle = 11 sqrt(2) as the two sides are equal due to the triangle being an isoceles triangle.
Solve for x by using Pythagorean theorem:



Hence answer is B. 22
From the figure, segment QP is in the ray RP and RP contains N and Q in between
so from the options, the two rays will be : ray QP and ray NP
For SU :
segment SU is in the ray RU and RU contains S and T in between,
so from the options again, the two rays will be : ray RU and ray SU