Hybrid Orbitals: are used to describe the orbitals in covalently bonded atoms sp,sp2,sp3
You can find the hybridization by adding the number of bonded atoms and the number of lone pairs.
For example in BF3. The central atom (B) is bonded to three atoms. So the hybridization is sp2
In NH3, the central atom (N) is bonded to three atoms and has one lone pair. The hybridization is sp3
Answer is: dispersion forces.
The London dispersion force is the weakest intermolecular force.
Dispersion force is also called an induced dipole-induced dipole attraction.
The London dispersion force (intermolecular force) is a temporary attractive force between molecules.
The dipole beetween iodine and bromine is weak.
The change in state from Liquid ➡ gas describes the process of evaporation.
Answer:
5 electron groups, see saw
Explanation:
During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.
SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.
Answer:
0.203 is the mean of the concentration of the HCl solution
Explanation:
You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:
0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =
<h3>0.203 is the mean of the concentration of the HCl solution</h3>
