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Burka [1]
3 years ago
12

Which of the following chemical equations is correctly balanced?

Chemistry
2 answers:
katrin2010 [14]3 years ago
6 0

Option B and C both are balanced.

A chemical reaction is said to be balanced if all the constituent on the left side of the reaction arrow are equal to right side.

(A) The chemical reaction is as follows:

H_{2}+O_{2}\rightarrow H_{2}O

There are 2 hydrogen atoms and 2 oxygen atoms on left side of the reaction arrow and 2 hydrogen and 1 oxygen on right hand side thus, number of oxygen atoms are not balanced.

Therefore, the above chemical reaction is not balanced.

(B) The chemical reaction is as follows:

2C_{2}H_{4}O+5O_{2}\rightarrow 4CO_{2}+4H_{2}O

There are 4 carbon atoms, 8 hydrogen atoms and 12 oxygen atoms on both side of the reaction arrow thus, the chemical reaction is balanced.

(C) The chemical reaction is as follows:

K_{2}S+I_{2}\rightarrow 2KI+S

There are 2 potassium atoms, 1 sulfur atom and 2 iodine atoms on both side of the reaction arrow thus, it is a balanced chemical reaction.

(D) The  chemical reaction is as follows:

CaCO_{3}+2HCl\rightarrow CaCl_{2}+2CO_{2}+H_{2}O

There is 1 calcium atom, 1 carbon atom, 3 oxygen atoms, 2 hydrogen atoms and 2 chlorine atoms on left side of the reaction arrow and 1 calcium atom, 2 chlorine atoms, 2 carbon atoms, 5 oxygen atoms and 2 hydrogen atoms on right hand side of the reaction arrow. Thus, number of carbon and oxygen atoms are not balanced in the chemical reaction.

olga55 [171]3 years ago
3 0
The correct answer is B.
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A student measures the volume of a solution to be 0.01370 have 5 significant digits in this measurement.

<h3>What are significant digits?</h3>

The significant digits are the minimum number from zero to nine for reporting any measurement where the digits are uncertain.

The significant digits starting from zero are not significant digits, decimal is not a significant digit, and ending zero after the decimal are significant digits.

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If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
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Answer is: mass of the ore is 8.54kg.<span>

</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
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The pressure in car tires is often measured in pounds per square inch ( lb/in.2 ), with the recommended pressure being in the ra
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when we convert 32.5 lb/in² to atmosphere, the result obtained is 2.21 atm

<h3>Conversion scale</h3>

14.6959 lb/in² = 1 atm

<h3>Data obtained from the question</h3>
  • Pressure (in lb/in²) = 32.5 lb/in²
  • Pressure (in ATM) =?

<h3>How to convert 32.5 lb/in² to atm</h3>

14.6959 lb/in² = 1 atm

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