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Tom [10]
3 years ago
11

If the strength of the magnetic field at A is 32 units, the strength of the magnetic field at B is _____.

Chemistry
2 answers:
Ahat [919]3 years ago
4 0
C 16 units, i think I'm not 100% sure
Pachacha [2.7K]3 years ago
4 0

Answer:

The correct answer 1 unit...

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The answer would be two
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4. What is the common name of the compound CaOCI,?​
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Answer:

Calcium Hypochlorite is an inorganic chemical compound with chemical formula CaOCl2. They are also called calcium oxychloride and the common name of CaOCl2 is bleching or chlorine powder.

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3 years ago
Which statement accurately describes differences between RNA and DNA?
Arlecino [84]

Answer:

RNA always folds into a single helix while DNA always folds into a double helix.

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8 0
2 years ago
Describing Chemical Reactions
nadya68 [22]

Answer:

mass of Liquid 1 + mass of Liquid 2 = mass of solid + mass of gas

Explanation:

iquid 1 reacts with Liquid 2, producing a solid and a gas. Using this scenario, which supports the law of conservation

of mass?

EEEE

O mass of Liquid 1 + mass of solid = mass of Liquid 2 + mass of gas

O mass of Liquid 1 - mass of solid = mass of Liquid 2-mass of gas

O mass of Liquid 1 - mass of Liquid 2 = mass of solid + mass of gas

O

based on the law of the conservation of matter, the sum of the masses of the reactants must equal  the sum of the masses of the products

so the correct answer is

mass of Liquid 1 + mass of Liquid 2 = mass of solid + mass of gas

7 0
3 years ago
A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
Read 2 more answers
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