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2 years ago

Intersecting Secant (Exterior) Find X =

Mathematics

1 answer:

levacccp [35]2 years ago

6 0

Answer: x = 13

Step-by-step explanation: the equation to solve this is:

4 × (4 + 8) = 3 × (3 + x)

so we solve the first half of that:

4 × (4 + 8)

4 × 12

now we have:

48 = 3 × (3 + x)

so we switch the sides to make it easier and solve

3 × (3 + x) = 48

divide both sides by 3

3 × (3 + x) ÷ 3 = 48 ÷ 3

and get

3 + x = 16

now subtract 3 from both sides

3 + x = 16

-3 -3

and finally we get

x = 13

hope this helped :)

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M is the midpoint of PQ, N is the midpoint of MQ, and L is the midpoint of MN. IfPQ = 64, find LN.

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Answer:

0 < x < 4
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Step-by-step explanation:

1. The solution is the set of x-values for which the graph is above the x-axis, where y = 0. Those x-values are in the interval (0, 4).

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3. The x-intercepts of the graph are x=0 or x=4.

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2 years ago

Can you find the missing angles?

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3 years ago

Read 2 more answers

According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health

katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74$

The probability is then

$P(X>65,000)=P(z>0.74)=0.22965$

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22$

The probability is then

$P(X>65,000)=P(z>1.22)=0.11123$

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?

To calculate the probability of earning less than $40,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05$

The probability is then

$P(X$

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

$X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133$

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

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3 years ago