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Lana71 [14]
3 years ago
12

Which expression is equivalent to 24 + 20​

Mathematics
1 answer:
Maslowich3 years ago
8 0
24+20=44
4(6+5)=44
the first one
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Kate has a stamps collection.In her collection 2/5 of the stamps are from the untied states and 1/4 are from Asia. These rest ar
rosijanka [135]

Answer:

I think the answer is...

13/20

Step-by-step explanation:

6 0
3 years ago
Solve the equation. Find all real solutions.<br> 9r3 - 144r = 0
Karolina [17]

Answer:

r=0

Step-by-step explanation:

9r x 3 - 144r = 0

27r-144r=0

-117r=0

r=0

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3 years ago
The area of a circle is 1441 m2.<br> What is the diameter of the circle?
gregori [183]

Hey there! I'm happy to help!

The area of a circle is the radius squared multiplied by pi (we will use 3.14). We already have the area, so we will go backwards.

1441÷3.14≈458.9171975

We find the square root.

√458.9≈21.42235275

Now we have our approximate radius. The diameter is twice the radius.

21.42235275×2=42.8447055

I don't know exactly if they want you to round it or not, but the diameter is somewhere around there.

Have a wonderful day! :D

6 0
3 years ago
Which of the following shapes has the greatest number of lines of symmetry
jeyben [28]
Circle has the greatest number of lines of symmetry
6 0
3 years ago
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Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.
galben [10]

Answer:

The interval of increase of g(x) is (-6,+\infty).

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be g(x) = 190 + 8 \cdot x^{3} + x^{4}, the first derivative of the function is:

g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}

g'(x) = 4 \cdot x^{2}\cdot (6+x)

The following condition must be met to define the interval of increase:

4\cdot x^{2} \cdot (x+6) > 0

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

x + 6 > 0

The solution to this inequation is:

x > - 6

Now, the solution to this expression in interval notation is: (-6,+\infty)

3 0
3 years ago
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