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DedPeter [7]
3 years ago
12

Y=x​2​​−6x+10​ y=4−x​​ How do I substitute?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

(2,2) and (3,1)

Step-by-step explanation:

Since we're given the value of y in the second equation, we can replace the y on the left side of the first equation with 4-x, giving us

4-x=x^2-6x+10\\0=x^2-5x+6

We can factor the expression on the right to get us

0=x^2-5x+6\\0=x^2-3x-2x+6\\0=x(x-3)-2(x-3)\\0=(x-2)(x-3)

Solving x-2=0 and x-3=0 gets us the solutions x=2,3, which we can plug into the second equation to get us

y=4-2=2\\y=4-3=1

So, our solution set is the pair of points (2,2) and (3,1)

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