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OLga [1]
3 years ago
12

PLEASE HELP 2x^2-8x+6=0

Mathematics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

x = 4 or x = -1

Step-by-step explanation:

2x^2 - 8x + 6 =0

divide by 2 we get  : x^2 -4x +3 = 0

(x -4) (x+1)

x = 4 or x = -1

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The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
<span>g(\theta)  has a period of 2π, then T_{g} =2T_{f}=2 \pi and T_{f}= \pi.
</span>
To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
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If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






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3 years ago
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Have a great day!

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2 years ago
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