The solution of the equation x2+7x is 0, -7 using the quadratic formula.
Step-by-step explanation:
x2 + 7x = 0
-b ± √
b2 - 4(ac)/ 2a
substitution,
a = 1, b = 7, c = 0
= -7 ± √(7)2 - 4(1 x 0) / 2 x 1
= - 7
± 7 / 2
x = 0 , -7
Answer:
r=5
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-3*(4*r-8)-(-36)=0
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
4r - 8 = 4 • (r - 2)
Equation at the end of step 2 :
(0 - 12 • (r - 2)) - -36 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
60 - 12r = -12 • (r - 5)
Equation at the end of step 4 :
-12 • (r - 5) = 0
Step 5 :
Equations which are never true :
5.1 Solve : -12 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : r-5 = 0
Add 5 to both sides of the equation :
r = 5
One solution was found :
r = 5
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Answer:
n<50
Step-by-step explanation:
7/2*5n + 14<49
7n/2*5+14<49
(7n)+(2*5)14/2*5 <49
7n+10*14/2*5 <49
7n+140/2*5 <49
7n+140/10 <49
7n+140 < 10*49
7n+140 < 490
(7n+140)+(-140)<490+(-140)
7n+140-140<490-140
7n<350
7n/7 < 350/7
n<2*5^2*7/7
n<2*5^2
n<2*25
n<50
Answer: 
Step-by-step explanation:
As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.
Using the identity 
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