5,120........................................
You have a line:
y=mx+b (slope-intercepted form)
m=slope of this line.
The slope of a line perpendicular to that given line will be: ´"m´"
m´=-1/m.
For example:
y=8x+3
m=8
The solpe fo a line perpendicular to "y=8x+3" is:
m`=-1/8
Answer:
Area of triangle is 9.88 units^2
Step-by-step explanation:
We need to find the area of triangle
Given E(5,1), F(0,4), D(0,8)
We will use formula:

We need to find the lengths of side DE, EF and FD
Length of side DE = a = 
Length of side DE = a = 
Length of side EF = b = 
Length of side EF = b = 
Length of side FD = c = 
Length of side FD = c = 
so, a= 8.60, b= 5.8 and c = 4
s = a+b+c/2
s= 8.6+5.8+4/2
s= 9.2
Area of triangle=
So, area of triangle is 9.88 units^2
Volume of a sphere and a cone
We have that the equation of the volume of a sphere is given by:

We have that the radius of a sphere is half the diameter of it:
Then, the radius of this sphere is
r = 6cm/2 = 3cm
<h2>Finding the volume of a sphere</h2>
We replace r by 3 in the equation:

Since 3³ = 3 · 3 · 3 = 27

If we use π = 3.14:

Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:
4.18666... ≅ 4.19
Then, we have that:

Then, we have that:
<h2>Finding the volume of a cone</h2>
We have that the volume of a cone is given by:

where r is the radius of its base and h is the height:
Then, in this case
r = 3
h = 6
and
π = 3.14
Replacing in the equation for the volume:

Then, we have:
3² = 9

Answer: the volume of the cone that has the same circular base and height is 56.52 cm³
Answer:
y = -1/5 x + 2
Step-by-step explanation:
y = 5x - 4
m = 5
Slope of perpendicular = -1/5
Equation of perpendicular:
y = mx + b
y = -1/5 x + b
Use point (15, -1) for x and y, and solve for b.
-1 = -1/5(15) + b
-1 = -3 + b
b = 2
Equation of perpendicular:
y = -1/5 x + 2