4x+2y=10 Equation 1
x-y=13 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=y+13
Substitute value of x in equation 1
4(y+13)+2y=10
4y+52+2y=10
6y+52=10
6y=-42
y=-7
Now substitute value of y in x=y+13
x=-7+13
x=6
Answer: (6,-7)
Answer:
A. 0.2
Step-by-step explanation:
First make the table.
<u>10-grade</u> <u>11-grade</u> <u>12-grade</u> <u>Total</u>
<u>Woodson high school </u> | 110 | 120 | 80 | 310 |
<u>Valley high school </u> | 180 | 150 | 120 | 450 |
<u>Riverside high school </u> | 160 | 140 | 200 | 500 |
<u>Total </u> | 450 | 410 | 400 | 1260 |
Question: In decimal form, to the nearest tenth, what is the probability that a randomly selected riverside high school student is in twelfth grade?
First, find 12-grade and riverside high school number. 200. Take the total lined up with total number, which is 1260, and divide 200 divided by 1260.
200/1260=0.2
The answer is 0.2.
Hope this helps!
If not, I am sorry.
Answer:
m = 0.5 / 2 = 0.25
Step-by-step explanation: