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labwork [276]
2 years ago
11

8. Lara invested a total of $1000 in two simple interest accounts. Account A pays

Mathematics
1 answer:
mixer [17]2 years ago
8 0

Answer:

  • $200 at 5%
  • $800 at 6%

Step-by-step explanation:

Let x represent the amount invested at the higher rate. Then 1000-x is the amount invested at the lower rate. The total earnings are ...

  0.05(1000-x) +0.06x = 58

  50 +0.01x = 58 . . . . . . . . . . . simplify

  0.01x = 8 . . . . . . . . . . . . . . . subtract 50

  x = 800 . . . . . . . . . . . . . . . multiply by 100; amount at 6%

  (1000-x) = 200 . . . . . . . find the amount invested at 5%

Lara invested $200 at 5% and $800 at 6%.

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If g(x)=3x-11, what is x is g(x)=289
Liula [17]

Answer:x=100

Step-by-step explanation:

Since you know that g(x)=3x-11 all you have to do is substitute that into g(x)=289. So you get 3x-11=289. To get x you have to add 11 on both sides.

3x-11=289

+11 +11

----------------

3x = 300

Divide 3 on both sides to get x by itself

3x =300

---- -------

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Joanna purchased four boxes of cookies for a party. Each box cost $3.28, including tax. PLEASE HELP!!! 100 POINTS!!! Which expre
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Answer:

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Step-by-step explanation:

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