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Harlamova29_29 [7]
3 years ago
9

HELP PLEASE solve the following equation for x. 9-x/2+2= SHOW WORK

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

9+2=x/2

11=x/2

11×2=x

x=22

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which expression is equivalent to the given expression? 3 (2a+5)....a) 11a. b)6a+15. c) 6a+5. or d) 21a
Afina-wow [57]
3(2a+5)
6a+15 divide both sides by 6
a=2.5
4 0
4 years ago
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Several years​ ago, 39​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
BaLLatris [955]
<h2>Answer with explanation:</h2>

Let p be the population proportion  of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Given : Several years​ ago, 39​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Set hypothesis to test :

H_0: p=0.39\\\\H_a :p\neq0.39

Sample size : n= 1055

Sample proportion : \hat{p}=\dfrac{466}{1055}=0.441706161137\approx0.44

Critical value for 95% confidence : z_{\alpha/2}=1.96

Confidence interval : \hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

0.44\pm (1.96)\sqrt{\dfrac{0.39(1-0.39)}{1055}}\\\\0.44\pm0.0299536805135\\\\0.44\pm0.03\\\\=(0.44-0.03, 0.44+0.03)\\\\=(0.41,\ 0.47)

Since , Confidence interval does not contain 0.39.

It means we reject the null hypothesis.

We conclude that 95​% confidence interval represents evidence that​ parents' attitudes toward the quality of education have changed.

8 0
4 years ago
0.18 divided by 0.04
tatiyna
If you plug that into a calculator you get 4.5
3 0
3 years ago
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The average number of calories in a 1.5-ounce chocolate bar is 225. Suppose that the distribution of calories is approximately n
s344n2d4d5 [400]

Answer:

The probability that a randomly selected chocolate bar will have a. Between 200 and 220 calories will be 0.3023

Step-by-step explanation:

Given:

True mean=225

S.D=10

X1=200 and X2=220

To Find:

P(X1<x<X2)

Solution:

<em>BY using Z-table for probability and Z-score we can proceed.</em>

So

For 200 calories Z will be ,

Z=(sample mean -true mean)/S.D

=200-225/10

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For 220 calories Z will be ,

Z=220-225/10

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So required probability will be

P(-2.5

=P(-2.5

=P(0>z>2.5)-P(0>z>0.5)

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6 0
3 years ago
Question 5
agasfer [191]

Step-by-step explanation:

Given

g(x) = - 2x² + 3x

g(3) = - 2 * 3² + 3 *3

= -2 * 9 + 9

= -18 + 9

= -9

5 0
3 years ago
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