Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

Answer: 
The answer for 7. and 6. is compare and contrast :)
#1: y= 0.5+3 x
which means that x= y/3 - 0.5
#2: y= 3(0.5) x
which means that y= 1.5 x
that means x = y/1.5
Hope it can help
Looking for the area of a regular figure would be taking the longest side and the shortest side and multiply
Answer:
It would be equal to 15 - (18)