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CaHeK987 [17]
3 years ago
13

Several years​ ago, 39​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r

eceive. A recent poll asked 1 055 parents who have children in grades​ K-12 if they were satisfied with the quality of education the students receive. Of the 1 055 ​surveyed, 466 indicated that they were satisfied. Construct a 95​% confidence interval to assess whether this represents evidence that​ parents' attitudes toward the quality of education have changed.
Mathematics
1 answer:
BaLLatris [955]3 years ago
8 0
<h2>Answer with explanation:</h2>

Let p be the population proportion  of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Given : Several years​ ago, 39​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

Set hypothesis to test :

H_0: p=0.39\\\\H_a :p\neq0.39

Sample size : n= 1055

Sample proportion : \hat{p}=\dfrac{466}{1055}=0.441706161137\approx0.44

Critical value for 95% confidence : z_{\alpha/2}=1.96

Confidence interval : \hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

0.44\pm (1.96)\sqrt{\dfrac{0.39(1-0.39)}{1055}}\\\\0.44\pm0.0299536805135\\\\0.44\pm0.03\\\\=(0.44-0.03, 0.44+0.03)\\\\=(0.41,\ 0.47)

Since , Confidence interval does not contain 0.39.

It means we reject the null hypothesis.

We conclude that 95​% confidence interval represents evidence that​ parents' attitudes toward the quality of education have changed.

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A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c
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The minimum sample size required to create the specified confidence interval is 2229.

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We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

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Classwork 12.1 surface area
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Answer:

6) LA = 90 units² and SA = 202 units²

7) LA = 377 units² and SA = 477.5 units²

8) LA = 208 units² and SA = 232 units²

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Step-by-step explanation:

* Lets revise the rules of lateral area and surface area

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