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Katena32 [7]
3 years ago
14

(Car Sales) Of the cars sold during the month of July, 88 had air conditioning, 96 had automatic transmission, and 76 had power

steering. 4 cars had all three of these extras. 19 cars had none of these extras. 23 cars had only air conditioning, 61 cars had only automatic transmissions, and 28 cars had only power steering. 11 cars had both automatic transmission and power steering. How many cars had air conditioning and automatic transmission but not power steering?
a) 37

b) 4

c) 7

d) 28

e) 24

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

e) 24

Step-by-step explanation:

Please see attachment

Shalnov [3]3 years ago
3 0

Answer:

Option E.

Step-by-step explanation:

Given information:

Air conditioning = 88

Automatic transmission = 96

power steering = 76

All three = 4

None of these extras = 19

Only air conditioning = 23

Only automatic transmissions = 61

Only power steering = 28

Both automatic transmission and power steering = 11

Place these values and draw a venn diagram as shown below.

Calculation for missing values:

11-4=7

96-61-4-7=24

88-24-4-23=37

From the given diagram it is clear that the number of cars that had air conditioning and automatic transmission but not power steering is 24.

Therefore, the correct option is E.

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Find the acute angle between the two given lines<br><br> y=-2x and y=x
Marina CMI [18]

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

3 0
3 years ago
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
2 years ago
4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (
Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0
2 years ago
Help please! find m∠bcf
77julia77 [94]

Answer:

BCF = 140°

See attached image.

5 0
2 years ago
Read 2 more answers
The two-way table shows the estimated number of students who will enroll in three area high schools next year. a 5-column table
mr Goodwill [35]

Answer:

A. 0.2

Step-by-step explanation:

First make the table.

                                          <u>10-grade</u>  <u>11-grade</u>  <u>12-grade</u>  <u>Total</u>

<u>Woodson high school </u>    |     110     |     120    |      80     |   310   |

<u>Valley high school </u>          |     180    |     150    |     120     | 450   |

<u>Riverside high school </u>     |     160    |     140    |     200    | 500   |

<u>Total </u>                                 |     450   |     410    |     400    | 1260 |

Question: In decimal form, to the nearest tenth, what is the probability that a randomly selected riverside high school student is in twelfth grade?

First, find 12-grade and riverside high school number. 200. Take the total lined up with total number, which is 1260, and divide 200 divided by 1260.

200/1260=0.2

The answer is 0.2.

Hope this helps!

If not, I am sorry.

6 0
2 years ago
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