Find 64% of 25. Use a fraction. 2. 14 15 16

Mathematics

2 answers:

mr Goodwill [35]3 years ago

5 0

Hey person hope you have a great day and download Socratic in the App Store it will really help you

andriy [413]3 years ago

4 0

36 divided by 85 gives you 10 hope this helped !:)

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An international company has

Alborosie

Total employees x 0.248 = 25,600
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4 years ago

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Find The derivative of:(cosx/1+sinx)^3

forsale [732]

Answer:

$-\frac{3 \cdot cos^2x}{(1+sinx)^3}$

Step-by-step explanation:

$y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})$ $[ y = x^n\ \ \ => \ \ \ \frac{dy}{dx} = b \cdot x^{n-1} \ ]$

$= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\$ $[\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ]$

$= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\$