Answer:
Part 1) Australia 
Part 2) China 
Part 3) Mexico 
Part 4) Zaire 
Step-by-step explanation:
we know that
The equation of a exponential growth function is given by

where
P(t) is the population
t is the number of years since year 2000
a is he initial value
r is the rate of change
Part 1) Australia
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 2) China
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 3) Mexico
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 4) Zaire
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Answer:
<h3><u>3 t = 6000 lb</u></h3>
Step-by-step explanation:
Hope it is helpful...
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.
Answer:
86in²
Step-by-step explanation:
Find the complete question attached
Area of the circle = πr²
Area of the square = L²
Length of the side of the square
r is the radius of the circle
r = L/2 = 20/2 =10in
Given
Length of the side of the circle = 20in
Area of the square = 20²
Area of the square = 400in²
Area of the circle =π(10)²
Area of the circle = 3.14(100)
Area of the circle= 314in²
Amount of plywood left over = 400in²-314in² = 86in²