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Dominik [7]
4 years ago
14

After college you start a job earning $40000 a year. You get a 6% raise each year. a) How much will you earn in year 2?

Mathematics
1 answer:
Elodia [21]4 years ago
7 0
The answer to Part a is $44,800. I did this by 40000*2*3/50 which comes out to 4,800 you add that to your beginning worth, 40,000. Part b is as follows; 9,600 which comes out to be $49,600. Replace the 2 in the original equation to be 40,000*4*3/50. The number '2' and '4' represent the years, and the 3/50 is equal to 6%. 6% in math terms is 3/50. The answer to part c is as follows; 40000*10*3/50 which comes out to be 24,000 so your final answer for part c is: $64,000 I hope this helped! Let me know if you need more work shown, and I'll add more! :)

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The mean score on a set of 17 test is 72. Suppose two more students take the test and score 68 and 63. What is the new mean?
Masja [62]

Answer:

New mean=71.32

Step-by-step explanation:

The expression for the total initial score is;

T=M×S

where;

T=total initial score

M=mean score

S=number in the set

replacing;

T=unknown

M=72

S=17

replacing;

T=72×17=1,224

The total initial score=1,224

Determine the total score by;

total score=total initial score+total final score

where;

total initial score=1,224

total final score=(68+63)=131

replacing;

total score=1,224+131=1,355

Determine the new mean;

New mean=total score/new number

where;

total score=1,355

new number=(17+2)=19

replacing;

new mean=1,355/19=71.32

8 0
3 years ago
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drek231 [11]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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slega [8]
9x + 26 + 7x - 17 = 2x + (-3x) + 5x =
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Step-by-step explanation:

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soln:

3x-5= 2x+10

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svetlana [45]

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