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3 years ago

Which expression is NOT equivalent to −3/8·(−4+1/2)? Drag this expression to the box.

Mathematics

1 answer:

Aleks [24]3 years ago

4 0

Answer:

The answer to your question is the first option

Step-by-step explanation:

Original expression

-3/8 (-4 + 1/2)

First option -3/8 (-4) + (3/8)(1/2) This option is not equivalent because

they forgot the negative sign of the

second term.

Second option (-3/8)(-4) + (-3/8)(1/2) This option is equivalent to the

original. Distributive property

Third option (-3/2)(-3 1/2) This option is equivalent to the original

Fourth option (-3/8)(-3) + (-3/8)(-1/2) This option is equivalent to the original

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What is the result if 3x-9 is evaluated when x = -5?

Anton [14]

Answer:

Step-by-step explanation:

I wonder if it is the minus that is causing the problem?

Let x = - 5

3*(-5) - 9

-15 - 9

This is a money question. If you are 15 dollars in debt and you spend another 9, where are you? (In the company of the American government. They do this all the time).

- 15 - 9 = - 24

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3 years ago

Where the image has the opposite orientation as the preimage

Elena L [17]

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3 years ago

PQRS is parallelogram,QM is the height of Q to SR and ON is the height from Q to PS.It SR =12 cm and QM =7.6 cm find the area of

Oksanka [162]

Given: SR=12cm, QM=7.6cm, PS=8cm.

Area of parallelogram=base×height

=12×7.6=91.2cm2.

Area of parallelogram=base×height

⇒91.2=8×QN

⇒QN=891.2=11.4cm.

5 0

3 years ago

A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if it is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7$

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that $n = 35, X = 0.95, s = 0.44$

Calculate the test statistic

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}$

$t = 3.36$

The test statistic is t = 3.36.

7 0

3 years ago

I need help please

Zina [86]

Answer:

Its out of A and C srry couldn't help much

8 0

3 years ago