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liberstina [14]
3 years ago
14

Is the point (0,0) a solution for this system?

Mathematics
1 answer:
Tresset [83]3 years ago
4 0

Answer:(0,0) is not a solution of the system.

Step-by-step explanation: I think.

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each get 66% of one pie.

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For how many integers $n$ is it true that $\sqrt{n} \le \sqrt{4n - 6} < \sqrt{2n + 5}$?
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\bf \sqrt{n}\leqslant \sqrt{4n-6}

\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}


namely, -5, -4, -3, -2, -1, 0, 1.  Excluding "2" because n < 2.

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If something is not a function does that mean x does repeat or no.
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What is (64x^2y^3)-1/2 as radical expression?
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\frac{1}{8xy \sqrt{y} }

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(64 {x}^{2}  {y}^{3} )^{  - \frac{ 1 }{2} }  \\  \\  =  \frac{1}{(64 {x}^{2}  {y}^{3} )^{\frac{ 1 }{2} } }  \\  \\  =  \frac{1}{ \sqrt{64 {x}^{2}  {y}^{3}} }  \\  \\  =  \frac{1}{ \sqrt{ {(8xy)}^{2} y} }  \\  \\  =  \frac{1}{8xy \sqrt{y} }

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