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2 years ago

A plumber has a set fee for a house call and charges by the hour for repairs. The total cost of

Mathematics

1 answer:

ratelena [41]2 years ago

6 0

Answer:

slope is the hourly rate of $110/hr

y-intercept is the set fee of 85

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CAN SOMEONE SHOW ME HOW TO DO THIS PLEASE????????????????

morpeh [17]

For (h+g)(x) you just add the two functions:

(h+g)(x) = 4x + 2x^2

For (h•g)(x) you multiply them:

(h•g)(x) = 4x • 2x^2 = 8x^3

For (h-g)(x) you subtract them:

(h-g)(x) = 4x - 2x^2

For (h-g)(-2) you sub -2 into the equation we just created:

(h-g)(-2) = 4(-2) - 2(-2)^2
(h-g)(-2) = -8 - 2(4)
(h-g)(-2) = -8 - 8
(h-g)(-2) = -16

5 0

3 years ago

Write an equation in slope-intercept form that passes through each pair of points. (0, 1) (-3, 1)

lina2011 [118]

Answer:

$y = \frac{0}{ - 3} + b$

Step-by-step explanation:

Slope intercept formula is y=mx+b

(m) is slope

(b) is the y intercept

We'll find slope first.

slope formula is

$\frac{y2 - y1}{x2 - x1}$

y2 and x2 are the y and x values of the second equation and y1 and x2 are the y and x values of the first equation.

So we just put the given values into our equation.

$\frac{1 - 1}{ - 3 - 0}$

Simplify

$\frac{0}{ - 3}$

Now we put this into our y=mx+b

y=0/-3x+b

now we need the (b)

to do this we take the values of one of the coordinates (doesn't matter which) and replace the (y) and (x) in our equation with them.

$y = \frac{0}{ - 3} x + b$

$1 = \frac{0}{ - 3} (0) + b$

Solve

1=0+b

b=1

Put this in our formula

$y = \frac{0}{ - 3} + 1$

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

6 0

2 years ago

How do you find the remaining side of a 45°-45°-90° triangle if the longest side is 28?

Irina-Kira [14]

Here you go! Hope this helps

3 0

2 years ago

Find the inverse of the rational function f(x)=2x/x+3

SashulF [63]

Answer:

${f(x)}^{ - 1} = \frac { - 3x}{x - 2}$

Step-by-step explanation:

check image above

sorry for my handwriting

5 0

3 years ago

If the distance from A (5,6) to B (1, b) is twice the distance from B to

Nimfa-mama [501]

Answer:

The possible values of $b$ are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that $AB = 2\cdot BC$ . By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

$AB = 2\cdot BC$

$\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}}$ (1)

Where:

$x_{A}$ , $x_{B}$ , $x_{C}$ - x-Coordinates of points A, B and C.

$y_{A}, y_{B}, y_{C}$ - y-Coordinates of points A, B and C.

$(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2} = 4\cdot (x_{C}-x_{B})^{2}+4\cdot (y_{C}-y_{B})^{2}$

Then, we expand and simplify the expression above:

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})$

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}$

If we know that $x_{A} = 5$ , $y_{A} = 6$ , $x_{B} = 1$ , $y_{B} = b$ , $x_{C} = 1$ and $y_{C} = -3$ , then we have the following expression:

$1 -10 +25 +b^{2} -12\cdot b+36 = 100 -8 +4 +36+24\cdot b +4\cdot b^{2}$

$b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132$

$3\cdot b^{2}+36\cdot b +80 = 0$

This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

$b_{1} \approx -2.944$ , $b_{2} \approx -9.055$

In consequence, the possible values of $b$ are -2.944 and -9.055, respectively.

8 0

3 years ago