The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:
General term of the arithmetic sequence.
, where d is the common difference.
d = 3
Put n = 2 in , we get
Put n = 3 in , we get
Put n = 4 in , we get
Put n = 5 in , we get
The first five terms of the sequence are 1, 4, 7, 10, 13.
Answer:
that correct answer is D, Substitute the coordinates x and y-value in the equation, (12 is the x-value, 10 is the y-value). 10 is not equal to 22 + 12, so the correct answer is D.
Hope this helps!
8r + 206 + 7r +79 = 360
15r + 285 = 360
15r = 75
r = 5
7(5) + 79
35 + 79
angle YMB is 114°
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
see the attached picture please
