You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
Answer:
it's the last one *25,000 J
Step-by-step explanation:
For 36 3 6 13. For 48 4 8 24. I think there are more but I can't think of them
In order to name the coordinates, you read the X axis first and then the Y axis. So A would be (-4, 4). B would be (-4, 6). C would be (2, 4).
They are not congruent because each angle is a different measure.
Hope this helped! :)
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}
