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Tamiku [17]
3 years ago
8

Can some help me with this algebra problem. I have done it several times but it seems to be wrong everytime

Mathematics
1 answer:
luda_lava [24]3 years ago
6 0

Answer:

x=25.61

Step-by-step explanation:

To determine the smallest amount, in dollars , that you can charge and make a profit of atleast $415, you need to find the value of x that gives p=415.

Substitute p=415 in the given quadratic equation and solve it for x.

415=-0.5x^{2} +36x-179

x^{2} -72x+1188=0

x=\frac{-(-72)+\sqrt{(-72)^{2}-4(1)(1188)} }{2(1)}

on solving we get x=25.61

The smallest amount you could charge and make a profit of $415 is $25.61

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Answer:

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Step-by-step explanation:

There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.

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<em>Additional comments</em>

This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.

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If you can typeset this, it is written ...

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This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.

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