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Tamiku [17]
4 years ago
8

Can some help me with this algebra problem. I have done it several times but it seems to be wrong everytime

Mathematics
1 answer:
luda_lava [24]4 years ago
6 0

Answer:

x=25.61

Step-by-step explanation:

To determine the smallest amount, in dollars , that you can charge and make a profit of atleast $415, you need to find the value of x that gives p=415.

Substitute p=415 in the given quadratic equation and solve it for x.

415=-0.5x^{2} +36x-179

x^{2} -72x+1188=0

x=\frac{-(-72)+\sqrt{(-72)^{2}-4(1)(1188)} }{2(1)}

on solving we get x=25.61

The smallest amount you could charge and make a profit of $415 is $25.61

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The linear model for the data is expressed as: R = 20p - 160.

<h3>How to Write a Linear Model?</h3>

Using two pairs of values from the table values, say, (32, 480) and (33, 500), find the unit rate (m).

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Substitute (p, R) = (32, 480) and m = 20 into R = mp + b to find b

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brainly.com/question/4074386

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