Question

What is the length of the longest side of a triangle that has vertices at (7, 6), (7, 1), and (-5, 6)?

Answer 1

I believe the answer is b, which is 13 units

Answer 2

Answer: The Answer is going to be B.

Step-by-step explanation:

We can find the distance between each pair of points using the distance formula Sqrt((x1-x2)^2 + (y1-y2)^2),(x1 and x2 are the x ordinates of each point, and y1 and y2 are the y ordinates. Sqrt stands for square root, and ^2 is to the power of two.

Using this we can find the side between 7,6 and 7,1 is 5.

The side between 7,1 and -5,6 is 13

The side between 7,6 and -5,6 is 12

After using the formula we can conclude the side between 7,1 and -5,6 is the longest, and it equals 13. Therefore the answer is B.