3 years ago

LOOK AT THE ATTACHMENT, PLS HELPPPPPPP!!

Mathematics

1 answer:

LenKa [72]3 years ago

8 0

Answer:

sorry i don't understand the writing..

Step-by-step explanation:

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Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, ver

Artemon [7]

Check the picture attached.

Let OB be the radius of circle with center O.

Let B' be the image of B after the described rotation

OB and OB' are sides of the equilateral triangle OBB'.

The x coordinate of B' is the midpoint of OB, that is 5.

In the right triangle B', point (5, 0) and B:

Distance point (5, 0) to B is 5
|B'B|=|OB|=10

so by the pythagorean theorem:

$a= \sqrt{ 10^{2} - 5^{2} } = \sqrt{ 2^{2} *5^{2} - 5^{2} }= \sqrt{5^{2}(4-1)}=5 \sqrt{3}$ units

Answer: $5 \sqrt{3}$